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Question

How many 7-digit numbers can be formed using the digits1,2,0,2,4,2,4?


  1. 420

  2. 450

  3. 360

  4. 340


Solution

The correct option is C

360


There are total of 7 digits, of which 2 appears 3 times, 4 appears 2 times and 1, 0 appear once each.So the required number of numbers
=7!/[3!*2!*1!*1!]
=420

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