How many carbon atoms are present in $0.35$ mole of $C_{6} H_{12} O_{6}$ ?

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Solution

$∵$ 1 mole of $C_{6} H_{12} O_{6}$ has $= 6 N$ atoms of $C$

$∴$ $0.35$ mole of $C_{6} H_{12} O_{6}$ has $= 6 \times 0.35$ N atoms of C $= 2.1 N$ atoms

$= 2.1 \times 6.023 \times 10^{23}$

$= 1.26 \times 10^{24} c a r b o n a t o m s$

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