How many cyclic isomers of $C_{5} H_{10}$ are possible?

4

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3

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2

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5

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Solution

The correct option is D $5$
$5$ isomers are possible. $C_{5} H_{10} (C_{n} H_{2 n}) .$ Molecules having the $C_{n} H_{2 n}$ formula are most likely to be cyclic alkanes. The five isomers are:
( Diagram )

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