How many diagonals are there in a hexagon?

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Solution

The correct option is D 9
Let there be 'n' sides of the polygen Number of diagonals
$= [\frac{n (n - 1)}{2} - n]$
$= [\frac{6 (6 - 1)}{2} - 6]$
$= \frac{6 \times 5}{2} - 6 = 9$

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