How many dichlorinated isomers can be formed by the halogenation of ${C H}_{3} {C H}_{2} {C H}_{2} {C H}_{3}$ with ${C l}_{2}$ in the presence of light?
(excluding stereoisomers)

2

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3

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5

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6

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Solution

The correct option is D $6$
Total $6$ isomers are possible.
Hence, option (D) is correct.

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Similar questions

D

C l_{2}

C H_{4}

130^{\circ} C

C H_{3} - C H_{3} | C | - C H_{3} C H_{2} - C H_{3} | C H - C H_{3}

B r_{2} / h u - --- \to

C H_{3} - C | C H_{3} H - C H_{2} - C H_{3} C l_{2} - - \to h v

(x)

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