Question

How many electrons are flowing per second past a point in a circuit in which there is a current of 5 amp?

Answer 1

Current, I = 5 A
Time, t = 1 s
Using the relation, I = Q / t:
Q = I x t
= 5 x 1 = 5 C
Now, if the charge is $1.6\times {10}^{-19}C$, the number of electrons is one.
So, if the charge is 5 C, the number of electrons is given by:
$\frac{1}{1.6\times {10}^{-19}}\times 5=31.25\times 10$¹⁸