How many electrons are present in 180 g of water?

1 mole

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10 moles

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18 moles

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100 moles

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Solution

The correct option is D 100 moles
1 mole $H_{2} O$ contain $1 \times 2 + 8 = 10 m o l e s$ electrons
$180 g H_{2} O = \frac{180}{18} = 10 m o l e H_{2} O$
$10 m o l e H_{2} O$ contains $10 \times 10 = 100 m o l e s$ electrons.

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