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Question

How many faradays are required to reduce 1 mol of $$Cr_2O_7^{2-}$$ to $$Cr^{3+}$$ in acidic medium?


A
2
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B
3
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C
5
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D
6
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Solution

The correct option is A 6

$$1 \ mol\ Cr_2O_7^{2-}$$ requires 6 moles electron $$= 6F$$ charge

$$\therefore$$ Number of Faraday's required $$= 6$$.

Hence, option D is correct.

673091_635354_ans_897dcaf81d3e44939f3276b4b67e0b89.jpg

Chemistry

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