You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Mole Concept

How many gram...

Question

How many grams of ammonia is obtained when 32.6 g of ammonium chloride reacts with calcium hydroxide during the laboratory preparation of ammonia?

$[2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3}]$

[N=14, H=1, O=16, S=32, Cl=35.5]

10.36 gm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

53.9 gm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

42. 95 gm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.18 gm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 10.36 gm
Reaction:

$2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3}$

$53.5$ gm of $N H_{4} C l$ produces $17 g$ of ammonia

So $32.6$ gm will give $17 \times \frac{32.6}{53.5} = 10.36$ gm NH $_{3}$

Hence, the correct option is $A$ .

Suggest Corrections

Similar questions

Q. The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by

N i C l_{2} . 6 H_{2} O

to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of

N i C l_{2} .6 H_{2} O

are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is .
(Atomic weights in g

m o l^{- 1}

H

= 1,

N

= 14,

O

= 16,

S

= 32,

C l

= 35.5,

C a

= 40,

N i

= 59)

Q. Ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by

N i C l_{2} .6 H_{2} O

to form a stable coordination compound (

[N i (N H_{3})_{6}] C l_{2}

). Assume that both the reactions are

100

% complete. If

1584

g of ammonium sulphate and

952

g of

N i C l_{2} .6 H_{2} O

are used in the preparation, the combined weight (in grams) of gypsum (

C a S O_{4} .2 H_{2} O

) and the nickel-ammonia coordination compound thus produced is ____.

(The reactions involved are:

C a (O H)_{2} + (N H_{4})_{2} S O_{4} \to 2 N H_{3} + C a S O_{4} .2 H_{2} O

N i C l_{2} .6 H_{2} O + 6 N H_{3} \to [N i (N H_{3})_{6}] C l_{2} + 6 H_{2} O

Atomic weights in

g m o l^{- 1}

H = 1, N = 14, O = 16, S = 32, C l = 35.5, C a = 40, N i = 59)

Q. Ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by

N i C l_{2} .6 H_{2} O

to form a stable coordination compound (

[N i (N H_{3})_{6}] C l_{2}

). Assume that both the reactions are

100

% complete. If

1584

g of ammonium sulphate and

952

g of

N i C l_{2} .6 H_{2} O

are used in the preparation, the combined weight (in grams) of gypsum (

C a S O_{4} .2 H_{2} O

) and the nickel-ammonia coordination compound thus produced is ____.

(The reactions involved are:

C a (O H)_{2} + (N H_{4})_{2} S O_{4} \to 2 N H_{3} + C a S O_{4} .2 H_{2} O

N i C l_{2} .6 H_{2} O + 6 N H_{3} \to [N i (N H_{3})_{6}] C l_{2} + 6 H_{2} O

Atomic weights in

g m o l^{- 1}

H = 1, N = 14, O = 16, S = 32, C l = 35.5, C a = 40, N i = 59)

Q. Ammonia reacts with sulphuric acid to give the fertilizer ammonium sulphate. Calculate the volume of ammonia [at STP] used to form

59 g

of ammonium sulphate.

[N = 14, H = 1, S = 32, O = 16]

Q. Write the equation for:
(i) The preparation of ammonia from ammonium chloride and calcium hydroxide.
(ii) The reaction of hydrogen chloride with ammonia.

Join BYJU'S Learning Program

How many grams of ammonia is obtained when 32.6 g of ammonium chloride reacts with calcium hydroxide during the laboratory preparation of ammonia?[2NH4Cl+Ca(OH)2→CaCl2+2H2O+2NH3][N=14, H=1, O=16, S=32, Cl=35.5]

The correct option is A 10.36 gmReaction:2NH4Cl+Ca(OH)2→CaCl2+2H2O+2NH353.5 gm of NH4Cl produces 17g of ammoniaSo 32.6 gm will give 17×32.653.5=10.36 gm NH3Hence, the correct option is A.

How many grams of ammonia is obtained when 32.6 g of ammonium chloride reacts with calcium hydroxide during the laboratory preparation of ammonia?

$[2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3}]$

[N=14, H=1, O=16, S=32, Cl=35.5]

The correct option is A 10.36 gm
Reaction:

$2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3}$

$53.5$ gm of $N H_{4} C l$ produces $17 g$ of ammonia

So $32.6$ gm will give $17 \times \frac{32.6}{53.5} = 10.36$ gm NH $_{3}$

Hence, the correct option is $A$ .