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Question

How many grams of ammonia is obtained when 32.6 g of ammonium chloride reacts with calcium hydroxide during the laboratory preparation of ammonia?

$$[2NH_4Cl+ Ca(OH)_2\rightarrow CaCl_2 + 2H_2O + 2NH_3]$$

[N=14, H=1, O=16, S=32, Cl=35.5]


A
10.36 gm
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B
53.9 gm
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C
42. 95 gm
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D
5.18 gm
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Solution

The correct option is A 10.36 gm
Reaction:

$$2NH_4Cl+ Ca(OH)_2\rightarrow CaCl_2 + 2H_2O + 2NH_3$$

$$53.5$$ gm of $$NH_4Cl$$ produces $$17 g$$ of ammonia

So $$32.6$$ gm will give $$17\times\dfrac{32.6}{53.5} = 10.36$$ gm  NH$$_3$$

Hence, the correct option is $$\text{A}$$.

Chemistry

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