Question

How many grams of carbon and oxygen are required to get the same number of atoms as is present in one gram of helium?

Answer 1

$1gHe\to \frac{1}{4}molHe$

No. of atoms $\alpha n$ of mols

$\therefore$ equal it mole equal

$1$ mol $C$ weighs $\to 12g$

$\frac{1}{4}$ mol $C$ weighs $\to 3g$

$1$ mol $O\to 36g$

$\frac{1}{4}$ mol $O\to 4g$