Question

How many grams of dibasic acid (mol. wt. 200) should be present in 100 mL of the aqueous solution to give 0.1 N ?

• A. 1 g
• B. 2 g
• C. 10 g
• D. 20 g

Answer 1

The correct option is A 1 g

Equivalent weight of dibasic acid
$=\frac{mol,wt.}{2}=\frac{200}{2}=100$

Strength = 0.1 N, m = ?, V= 100 ml.

From, $m=\frac{EVN}{1000}=\frac{100\times 100\times 0.1}{1000}=1g$

Hence, the correct option is $A$