Question

# How many grams of Na2SO4 can be produced from 260 gm of 90% pure NaCl when treated with excess of H2SO4? 255 gm 173 gm214 gm 284 gm

Solution

## The correct option is D 284 gm 2NaCl+H2SO4→Na2SO4+2HCl 117 gm                        142 gm Since, 117 gm NaCl produces 142 gm Na2SO4=  1 gm NaCl produces=142117 gm Na2SO4 So, 90% pure NaCl of 260 gm has (260×90100=234 gm) NaCl and will produce = 142117×(234)=284 gm Na2SO4

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