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Question

How many isomers of $${C}_{5}{H}_{11}OH$$ will be primary alcohols?


A
5
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B
4
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C
3
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D
2
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Solution

The correct option is B $$4$$
$$CH_3CH_2CH_2CH_2CH_2-OH$$;    $$CH_3-\overset{CH_3}{\overset{|}{CH}}-CH_2-CH_2-OH$$
$$CH_3-\overset{CH_3}{\overset{|}{\underset{CH_3}{\underset{|}{C}}}}-CH_2-OH$$;   $$CH_3-CH_2-\underset{CH_3}{\underset{|}{CH}}-CH_2-OH$$

Chemistry

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