How many lines does a spectrum contain in an electronic transition from $n = 1 t o n = 5$ in hydrogen atom?

10

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8

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1

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Solution

The correct option is A $10$
The no. of spectral lines produced in a spectrum = $\frac{(n_{2} - n_{1}) (n_{2} - n_{1} + 1)}{2}$ .
Given that $n_{2}$ = 5 and $n_{1}$ = 1; the no. of spectral lines = $\frac{4 \times 5}{2}$
$= 10.$

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How many lines does a spectrum contain in an electronic transition from n=1ton=5 in hydrogen atom?

The correct option is A 10The no. of spectral lines produced in a spectrum = (n2−n1)(n2−n1+1)2.Given that n2 = 5 and n1 = 1; the no. of spectral lines = 4×52 =10.

How many lines does a spectrum contain in an electronic transition from $n = 1 t o n = 5$ in hydrogen atom?

The correct option is A $10$
The no. of spectral lines produced in a spectrum = $\frac{(n_{2} - n_{1}) (n_{2} - n_{1} + 1)}{2}$ .
Given that $n_{2}$ = 5 and $n_{1}$ = 1; the no. of spectral lines = $\frac{4 \times 5}{2}$
$= 10.$