How many minimum no.of C-atoms are required for position & geometrical isomerism in alkene?

4,3

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4,4

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3,4

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3,3

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Solution

The correct option is B 4,4
The smallest alkene showing geometrical isomerism is $b u t - 2 - e n e$ ( $4 - C$ atoms)
The smallest alkene showing position isomerism is butene ( $4 - C$ atoms), where the position of double bonds may vary.
Hence, answer is $4, 4$

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