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Question

How many moles are present in $$6.023 \times 10^{22}$$ molecules of $$CO_2$$?


A
0.1 mole
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B
1 mole
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C
10 moles
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D
100 moles
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Solution

The correct option is C $$0.1$$ mole
As we know, 
One mole of $$CO_2$$ contains $$6.023\times 10^{23} molecules.$$

So, 
$$6.023\times 10^{22} $$ molecules of$$ CO_2\rightarrow \dfrac{6.023\times10^{22}}{6.023\times 10^{23}} = 0.1 mole$$

Hence, option A is correct.

Chemistry

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