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Question

How many moles of $${ KMnO }_{ 4 }$$ are reduced by $$1$$ mole of ferrous oxalate in acidic medium?


A
15
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B
53
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C
13
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D
35
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Solution

The correct option is A $$\cfrac { 3 }{ 5 } $$
In acidic medium,
$$3{ KMnO }_{ 4 }+5Fe{ C }_{ 2 }{ O }_{ 4 }+24{ H }^{ + }\longrightarrow 3{ K }^{ + }+3{ Mn }^{ 2+ }+5{ Fe }^{ +3 }+10{ CO }_{ 2 }+12{ H }_{ 2 }O$$

Here, $$3$$ moles of $${KMnO}_{4}$$ reduces $$5$$ moles of $${ FeC }_{ 2 }{ O }_{ 4 }$$.

$$\therefore \cfrac { 3 }{ 5 } $$ moles of $${KMnO}_{4}$$ reduces $$1$$ mole of $${FeC}_{2}{O}_{4}$$.

Hence, option $$D$$ is correct.

Chemistry

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