Question

# How many moles of $${ KMnO }_{ 4 }$$ are reduced by $$1$$ mole of ferrous oxalate in acidic medium?

A
15
B
53
C
13
D
35

Solution

## The correct option is A $$\cfrac { 3 }{ 5 }$$In acidic medium,$$3{ KMnO }_{ 4 }+5Fe{ C }_{ 2 }{ O }_{ 4 }+24{ H }^{ + }\longrightarrow 3{ K }^{ + }+3{ Mn }^{ 2+ }+5{ Fe }^{ +3 }+10{ CO }_{ 2 }+12{ H }_{ 2 }O$$Here, $$3$$ moles of $${KMnO}_{4}$$ reduces $$5$$ moles of $${ FeC }_{ 2 }{ O }_{ 4 }$$.$$\therefore \cfrac { 3 }{ 5 }$$ moles of $${KMnO}_{4}$$ reduces $$1$$ mole of $${FeC}_{2}{O}_{4}$$.Hence, option $$D$$ is correct.Chemistry

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