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Question

How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl? (Atomic wt. of Pb= 207)


PbO+2HClPbCl2+H2O

A
0.011
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B
0.029
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C
0.044
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D
0.333
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Solution

The correct option is B 0.029
PbO+2HClPbCl2+H2O

Atomic mass of PbO = 207 + 16 = 223
Atomic mass of HCl = 36.5

Moles of PbO = 6.5223 = 0.029 moles

Moles of HCl = 3.236.5 = 0.088 moles

From the above chemical equation, we see that PbO is the limiting reagent.

1 mole of PbO gives 1 mole of PbCl2

0.029 moles of PbO forms 0.029 moles of PbCl2.

Hence, the answer is option B.

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