How many moles of $N a O H$ are required to neutralize $1.2$ moles of $H_{2} S O_{4}$ ?

0.6 mole

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1.2 mole

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2.4 mole

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3.6 mole

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4.8 mole

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Solution

The correct option is C 2.4 mole
2.4 moles of $N a O H$ are required to neutralize 1.2 moles of $H_{2} S O_{4}$
$H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O$
Thus one mole of $H_{2} S O_{4}$ is neutralised with 2 moles of $N a O H$ .
1.2 moles of $H_{2} S O_{4}$ will be neutralised with $1.2 \times \frac{2}{1} = 2.4$ moles of NaOH.

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How many moles of NaOH are required to neutralize 1.2 moles of H2SO4?

The correct option is C 2.4 mole2.4 moles of NaOH are required to neutralize 1.2 moles of H2SO4 H2SO4+2NaOH→Na2SO4+2H2OThus one mole of H2SO4 is neutralised with 2 moles of NaOH.1.2 moles of H2SO4 will be neutralised with 1.2×21=2.4 moles of NaOH.

How many moles of $N a O H$ are required to neutralize $1.2$ moles of $H_{2} S O_{4}$ ?