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Question

How many moles of sodium oxalate. Na2C2O4, are present in 6.7 g of this compound?

(Atomic weights: C=12,O=16,Na=23 g/mole)

A
2.0 moles
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B
1.0 mole
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C
0.50 moles
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D
0.10 moles
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E
0.050 moles
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Solution

The correct option is E 0.050 moles
Atomic weights: C=12,O=16,Na=23
The molecular weight of sodium oxalate Na2C2O4 is 2(23)+2(12)+4(16)=46+24+64=134 g/mol.
Mass of sodium oxalate is divided with its molecular weight to obtain the number of moles.
Mass of sodium oxalate =6.7134=0.050 moles.

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