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Question

How many numbers greater than a million can be formed with the digits 5, 5, 2, 2, 1, 7, 0?

A
980
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B
1080
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C
920
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D
1200
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Solution

The correct option is B 1080
6654321
Since left most place can assume only non -zero digit and rest can assume all the given digits.
Therefore the number of numbers = 6.(6!)
But since 5 occurs 2 times and 2 occurs 2 times
Hence the required number of numbers =6.(6!)2!.2! = 1080

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