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Question

How many oxygen atoms are present in 50g of CaCo3 ?


A

3.011

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B

6.022

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C

9.033

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D

12.044

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Solution

The correct option is C

9.033


Molecular Mass of CaCo3 = (40 × 1) + (12 × 1) + (16 × 3) = 100g
100g of CaCo3 = 1 mole of CaCo3
50g of CaCo3 = 0.5 mole of CaCo3
1 mole of CaCo3=3×6.022×1023atoms of Oxygen0.5 mole of CaCo3=32×6.022×10(23)atomsofOxygen=9.033×1023 atoms of oxygen


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