The correct option is C 1000
Volume of cube = (side)3 or a3
Volume of each small cube = 203 = 8000cm3 = 0.008m3
Now, volume of the cubical box = 23 = 8m3
Therefore, no. of small cubes, that can just be accommodated in the cubical box = Vol.ofcubicalboxVol.ofsmallcube = 80.008 = 1000