Question

How many spherical balls can be made out of a solve cube of lead whose edge measure $44cm$ and each ball being $4cm$ in diameter.

Answer 1

Let n balls be made

As volume of malarial would be constant

$\Rightarrow$ volume of cube = volume of n spherical balls

$\Rightarrow (edge{)}^3=n\times \frac{4}{3}\pi r^3$ $\left\{radiusofballs\right\}$

$\Rightarrow (44{)}^3=n\times \frac{4}{3}\pi (\frac{4}{2}{)}^3$

$\Rightarrow (44{)}^3=\frac{4\pi }{3}\times n\times 8$

$n=\frac{{44}^3\times 3}{4\pi \times 8}=\frac{{44}^2\times 44\times 3\times 7}{24\times 22\times 8}=2541.$