CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

How many spherical bullets can be made out of a solid cube of lead whose edge measures $$44\space cm$$, each bullet being $$4\space cm$$ in diameter.


A
2451
loader
B
2541
loader
C
2304
loader
D
2536
loader

Solution

The correct option is A $$2541$$

Number of spherical bullets formed $$ = \dfrac {Volume  of 
cube}{Volume   of   one   spherical  bullet} $$


Volume of a cube of edge a $$ = {a}^{3} $$



 Volume of a sphere of radius 'r' $$ = \dfrac { 4 }{ 3 } \pi { r }^{ 3 } $$


As the diameter of the sphere is $$4$$ cm, its radius r $$ = 2$$ cm



Hence, number of spherical bullets formed $$ = \dfrac {44 \times 44 \times 44}{\dfrac {4}{3}
\times \dfrac {22}{7} \times 2 \times 2 \times 2} = 2541 $$


Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image