Question

# How many spherical bullets can be made out of a solid cube of lead whose edge measures $$44\space cm$$, each bullet being $$4\space cm$$ in diameter.

A
2451
B
2541
C
2304
D
2536

Solution

## The correct option is A $$2541$$Number of spherical bullets formed $$= \dfrac {Volume of cube}{Volume of one spherical bullet}$$ Volume of a cube of edge a $$= {a}^{3}$$ Volume of a sphere of radius 'r' $$= \dfrac { 4 }{ 3 } \pi { r }^{ 3 }$$As the diameter of the sphere is $$4$$ cm, its radius r $$= 2$$ cmHence, number of spherical bullets formed $$= \dfrac {44 \times 44 \times 44}{\dfrac {4}{3}\times \dfrac {22}{7} \times 2 \times 2 \times 2} = 2541$$Mathematics

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