How many times the volume of a cone decreases if the radius of the base is reduced by half?

Open in App

Solution

Volume of cone $= \frac{1}{3} π r^{2} h = v$
When, radius is reduced by half.
$V_{1} = \frac{1}{3} π (\frac{r}{2})^{2} h = \frac{1}{3} \frac{π r^{2} h}{4} V_{1} = \frac{v}{4}$

Suggest Corrections

Similar questions

If the radius of the base of a cone is halved,keeping the height same, what is the ratio of the volume of the reduced cone to that of the original cone?

If the radius of the base of a right circular cone is increased by 15%, then the volume of the cone will increase by ______.

Q. If the height of a right circular cone is increased by 100% and the radius of the base is reduced by 50%, then the volume of the cone

Q. Volume of a cylinder is how many times more than a cone with same radius and height. ?

Q. If the radius of the base of a right circular cone is halved, keeping the height same, then the ratio of the volume of the reduced cone to that of the original cone is

Join BYJU'S Learning Program

How many times the volume of a cone decreases if the radius of the base is reduced by half?

Volume of cone =13πr2h=v When, radius is reduced by half. V1=13π(r2)2h=13πr2h4V1=v4

Volume of cone $= \frac{1}{3} π r^{2} h = v$
When, radius is reduced by half.
$V_{1} = \frac{1}{3} π (\frac{r}{2})^{2} h = \frac{1}{3} \frac{π r^{2} h}{4} V_{1} = \frac{v}{4}$