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Question

How many two digit odd numbers are there with 10 factors?
  1. None of these
  2. 2
  3. 3
  4. 1


Solution

The correct option is A None of these

10 factors implies that the number can be of the form

1) a9 ( Least odd number will be 39)

2) ab4 (Least odd number will be 34×5=405)

Therefore, as the least number is 405, there are no two digit numbers of the specified form. The answer is 0.

Note - If a number N can be factorized as N=am×bn (where a, b are the prime factors)

Then, number of factors of N = (m+1)(n+1)

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