How many unique ways are there to arrange the letters of the word $^{'} P R I O R^{'}$

60

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120

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180

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150

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Solution

The correct option is A $60$
PRIOR
Number of letters $= 5$
Out of which $R$ is repeated twice
$\Rightarrow$ There are $4$ diffrent letters
Total number of arrangements
$= \frac{5!}{2} = \frac{120}{2} = 60$

Therefore possible ways $= 60$

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