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Question

How many unit cells are present in a cube-shaped ideal crystal of $$\text{NaCl}$$ of mass $$1.00$$ g?


A
1.03×1022 unit cells
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B
2.57×1021 unit cells
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C
1.28×1021 unit cells
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D
1.71×1021 unit cells
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Solution

The correct option is B $$2.57\times 10^{21}$$ unit cells
One unit of $$\text{NaCl}$$ contains $$4$$ $$\text{NaCl}$$ molecules $$=\dfrac{4\times58.5}{6.023\times 10^{23}}$$ g

Number of unit cells in $$1$$ g $$=\dfrac{6.023\times10^{23}}{4\times58.5} \implies 2.57\times 10^{21}$$

Chemistry

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