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Nylon-6,6

How much calc...

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How much calcium carbide is needed to produce 1.60kg polyethyne ?

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Q. Formation of polyethene from calcium carbide takes place as follows:

C a C_{2} + H_{2} O \to C a (O H)_{2} + C_{2} H_{2} C_{2} H_{2} + H_{2} \to C_{2} H_{4}

n (C_{2} H_{4}) \to (- C H_{2} - C H_{2} -)_{n}

The amount of polyethylene possibly obtainable from 64.0 kg

C a C_{2}

Q. Mass of calcium carbide,

{C a C}_{2}

, would be needed to produce

150 g

C_{2} H_{2}

by using excess of water?

Q. Calcium carbide reacts with water to produce:

Q. Formation of polyethylene from calcium carbide takes place as follows:

C a C_{2} + 2 H_{2} O ⟶ C a {(O H)}_{2} + C_{2} H_{2}

C_{2} H_{2} + H_{2} ⟶ C_{2} H_{4}

n C_{2} H_{4} ⟶ {(- {C H}_{2} - {C H}_{2} -)}_{n}

The amount of polyethene obtained from

64.1 k g

C a C_{2}

Q. Calcium carbide is made in an electric-furnace by the following reaction :

C a O + 3 C ⟶ C a C O_{2} + C O

The crude product is usually

85 %

C a C_{2}

15 %

C a O

C a O

should we start with to produce

450

kg of crude product?
(Given that molecular weight of

C a = 40, C = 12, O = 16

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