Question

# How much energy is required to change $$2\ Kg$$ of ice at $${0}^{0}C$$ into water at $${20}^{0}C$$? (specific latent of heat of fusion of water = $$3,34,000J/Kg$$, specific heat capacity of water = $${4200}\ {J}{Kg}^{-1}{K}^{-1}$$).

Solution

## Total heat= $$\left[\text{Heat required to convert 2 kg of ice to 2 kg of water at } O^oC\right]+$$                    $$\left[\text{Heat required to convert 2 kg of water at } o^oC\text{ to 2kg of water at}20^oC\right]$$$$=mh_{fg}+mC_p\Delta T$$$$=(2 \times 334 kJ)+(2 \times 4.2 \times 20)$$$$=668+168=836 kJ$$ of heat is required.Chemistry

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