CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Question 62

How much is y412y2+y+14 greater than 17y3+34y251y+68?


Solution

Required expression is
y412y2+y+14(17y3+34y251y+68)=y412y2+y+1417y334y2+51y68
On combining the like terms.
=y412y234y2+y+51y+146817y3=y446y2+52y17y354=y417y346y2+52y54
So, y412y2+y+14 is y417y346y2+52y54 greater than  17y3+34y251y+68.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More...


Same exercise questions
QuestionImage
QuestionImage
View More...



footer-image