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Question

How much momentum does a dumbbell of mass 10 kg transfer to the floor if it falls from a height of 80 cm (assume that the dumbbell stops after hitting the ground, and take g=10 ms2)?


  1. 40 kg m/s

  2. 50 kg m/s

  3. 35 kg m/s

  4. 30 kg m/s


Solution

The correct option is A

40 kg m/s


Given: Mass of the dumbbell, m=10 kg,
Distance covered by the dumbbell, s=80 cm=0.8 m,
Acceleration in the downward direction, a=10 ms2Initial velocity of the dumbbell, u=0

Let the final velocity of the dumbbell(when it is about to hit the floor) be v.
According to the third equation of motion:
v2u2=2asv=u2+(2×a×s)
v=0+(2×10×0.8)=4 ms1

Momentum=mass×velocity
p=10 kg×4ms1=40 kgms1

Hence, the momentum with which the dumbbell hits the floor is
40 kgms1

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