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Question

How much water should be mixed with 12 mL of alcohol so as to obtain 12% alcohol solution ?

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Solution

Volume of solute = 12 ml
Volume of solution = volume of solute + volume of solvent
Volume of solvent = volume of solution – volume of solvent
= 100 – 12 = 88 ml

concentration=Volume of solutevolume of solute+volume of solvent×10012=1212+x×100x=88

So, 88 ml of water will be added to 12 ml of alcohol in order to prepare a concentration 12%.

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