How to balance the chemical equation of photosynthesis
$C O_{2} + H_{2} O ⟶ C_{6} H_{12} O_{6} + H_{2} O + O_{2}$

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Solution

$C O_{2} + H_{2} O ⟶ C_{6} H_{12} O_{6} + H_{2} O + O_{2}$

Balance carbon by multiplying $C O_{2}$ by 6.
$6 C O_{2} + H_{2} O ⟶ C_{6} H_{12} O_{6} + H_{2} O + O_{2}$
Since, we have 13 oxygen atoms and 2 hydrogen atoms on the left side.
And on the right side, we have 14 hydrogen atoms and 10 oxygen atoms.
Thus, to balance both, first balance the hydrogen atoms on both sides by multiplying $H_{2} O$ by 9 on left side and multiplying by 3 on right side.
$6 C O_{2} + 9 H_{2} O ⟶ C_{6} H_{12} O_{6} + 3 H_{2} O + O_{2}$
Now, we have 12+9 = 13 oxygen atoms on left and 6+3+2 = 11 oxygen atoms on right.
Thus, we will multiply $O_{2}$ by 6.
Therefore, the balanced equation is
$6 C O_{2} + 9 H_{2} O ⟶ C_{6} H_{12} O_{6} + 3 H_{2} O + 6 O_{2}$

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Is the given equation correct? If not, correct it.

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