Question

# How to find area of curve using definite integral?

Solution

## The drawn curve here represents f(x)=x2+3x+4 Now, let us say, you want area covered by this curve and x-axis between x=1 and x=3, it is shown ln hatched portion. F(x)=x2+3x+4 so we integrate it, between x=1 and x=3 ∫31(s2+3x+4)dx=x23+3x22+4.x2 Now the inter and on R.H.S for x=3 first and then subtract the value of R.H.S for x=3.  This gives you the area between the curve fof x2+3x+4 and x-axis between x=1 and x=3. →(333+322+4,3)−(13+3.12+4)→(9+13.5+12)−(0.333+1.5+4)→34.5−5.833=28.667 sq.units Area under curve x2+3x+4 between x=1 and x=3−∫31(s2+3x+4)dx =28.667 sq. units (as calculated above)Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More