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Question

HX is a weak acid (Ka=105). It forms a salt NaX having concentration of 0.1M, on reacting with caustic soda. What is the  degree of hydrolysis (h) of the salt?
  1. 104
  2. 102
  3. 106
  4. 105


Solution

The correct option is A 104
Given, Ka=105, [NaX]=0.1 M
According to question,  NaX is a salt of weak acid and strong base.
Therefore X only undergoes hydrolysis. 
at equilibrium we have,
XCCh+H2OKaHXCh+OHCh


'Kh' is hydrolysis constant and 'C' is concentration
Kh=[HX][OH][X]
we know,
Kh=KwKa=1014105
Kh=109
we know
h=KhC=1090.1=108
h=104
degree of hydrolysis (h)=104
and also
percentage degree of hydrolysis=104×100=0.01

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