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Question

Hydrazine (N2H4) can be produced according to the following reaction:
ClNH2+2NH3N2H4+NH4Cl. 1 kg of ClNH2 is reacted with excess NH3, find the actual number of molecules of N2H4 produced if the percentage yield of the given reaction is 76%.

A
15NA
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B
13NA
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C
17NA
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D
3.2NA
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Solution

The correct option is A 15NA
ClNH2+2NH3N2H4+NH4Cl
It is given that 1 kg of ClNH2 reacts with excess NH3. Percentage yield of reaction is given as 76%, we need to find number of molecules of N2H4
Moles of ClNH2=MassMolar mass=1000 g51.5 g mol1 = 19.4 mol
From the balance reaction, it is clear that 1 mole of ClNH2 produces 1 mole of N2H4. Hence, 19.4 mol of ClNH2 produces 19.4 mol of N2H4.
From the percentage yield, the given actual moles of N2H4 will be
Actual moles of N2H4 = 19.4×0.76=14.74 mol
Number of molecules of N2H4=14.74 NA

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