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Question

Hydrogen atom in ground state is excited by a monochromatic radiation of λ=975 A. Number of spectral lines in the resulting spectrum emitted will be

A
3
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B
2
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C
6
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D
10
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Solution

Step 1: Given

Wavelength , λ=975Ao

Step 2: Formula used and Calculation

Energy incident =hcλ
Energy incident =hcλ=6.63×1034×3×108975×1010×1.6×1019eV
=12.75 eV

Now,

Energy for 1st orbit is 13.6eV

Energy for 4th orbit is 0.85eV

Difference =12.75eV
The hydrogen atom will be excited to n = 4
Therefore, number of spectral lines =4(41)2=6


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