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Question

[(I/11)-1 + (1/5)-2 ]3/2


Solution

(1/11)^-1=(11/1)^1=11
(1/5)^-2=(5/1)^2=5^2=25
Therefore [(I/11)-1 + (1/5)-2 ]3/2  
                 =(11+25)^3/2=(36)^3/2=(6^2)^3/2
                 =6^(2*3/2)=6^3
                 =216

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