I- 4 x2-19 x-12-0II- 3 y 2-8 y -4-0A- If x-yB- If x - yC- If x-yD- If x - yE- If x-y or cannot be established

The correct option is A If x gt; yIfx gt;y (x 4)(4x 3)=0 x=4, 3/4 (y+2)(3y+2)=0 y= 2, 2/3 4, 3/4, 2/3 2 ∴ x gt; y ...

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Addition of Rational Expressions

I. 4 x2-19 x+...

Question

I. $4 x^{2} - 19 x + 12 = 0$
II. $3 y^{2} + 8 y + 4 = 0$

x > y

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x < y

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x \leq y

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x \geq y

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x = y

or cannot be established

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Solution

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