I. 9 $x^{2}$ - 18 + 5 = 0

II. 2 $y^{2}$ - 9y + 10 = 0

if x < y

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if x = y

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Solution

The correct option is A
if x < y

$9 x^{2} - 18 x + 5 = 0$

$9 x^{2} - 3 x - 15 x + 5 = 0$

$3 x (3 x - 1) - 5 (3 x - 1) = 0$

$(3 x - 1) (3 x - 5) = 0$

$x = \frac{1}{3}, \frac{5}{3}$

$2 y^{2} - 9 y + 10 = 0$

$y = 2, \frac{5}{2}$

x < y

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