CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

I=(x+x23+x16)x(1+x13)dx is equal to
(where c is constant of integration)

A
32x23+6tan1(x16)+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
32x236tan1(x16)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
32x23+tan1(x16)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 32x23+6tan1(x16)+c
Substituting x=p6,dx=6p5dp, we have
I=6p5(p6+p4+p)p6(1+p2)dp=6(p5+p3+1)(p2+1)dp=6{p3(p2+1)+1}(p2+1)dp
=6p3dp+(6p2+1)dp=6p44+6tan1p+c=32x23+6tan1(x16)+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon