Question

(I) $H_{2}C=\stackrel{+}{N}=\stackrel{-}{N}$

(II) $H_2\stackrel{+}{C}-N=\stackrel{-}{N}$

(III) $H_2\stackrel{-}{C}-\stackrel{+}{N}=N$

(IV) $H_2\stackrel{-}{C}-N=\stackrel{+}{N}$

The correct stability order of the following resonance structure is:

• A. I $>$ II $>$ IV $>$ III
• B. I $>$ III $>$ II $>$ IV
• C. II $>$ I $>$ III $>$ IV
• D. III $>$ I $>$ IV $>$ II

Answer 1

The correct option is A I $>$ II $>$ IV $>$ III

The structure $\left(I\right)$ will be most stable as compared to others as it has two $pi$ bonds and all the octets are complete. In structure $III$ & $IV$ negative charge is present on less electronegative atom and positive charge is present on more electronegative atom.

So, the correct stability order will be, $I>II>IV>III$