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Question

(I) H2C=+N=N
(II) H2+CN=N
(III) H2C+N=N
(IV) H2CN=+N
The correct stability order of the following resonance structure is:

A
I > II > IV > III
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B
I > III > II > IV
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C
II > I > III > IV
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D
III > I > IV > II
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Solution

The correct option is A I > II > IV > III
The structure (I) will be most stable as compared to others as it has two pi bonds and all the octets are complete. In structure III & IV negative charge is present on less electronegative atom and positive charge is present on more electronegative atom.
So, the correct stability order will be, I>II>IV>III

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