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Question

(i) How much electricity in terms of Faraday required to produce.

20.0 g of Ca from molten CaCl2P

(ii) How much electricity in terms of Faraday required to produce.


Solution

(i) Electrode reaction : Ca2+(aq)+2e2FCa(s)40g

To produce 40g of Ca from molten CaCl2, electricity required = 2F To produce 20 g Ca from CaCl2, electricity required = 1F

(ii) Electrode reaction Al2O3(l)+6e6F2Al[(2+3O×27)=54g]+3O2

To produce 54g Al from molten A2O3, electricity required = 6F To produce 40 g Al from molten Al2O3, electricity required

=(6F)×(40g)(54g)=4.44F


Chemistry
NCERT Textbook
Standard XII

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