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Question

I: If a=3^i2^j+^k, b=2^i4^j3^k, c=^i+2^j+2^k then a+b+c=4^i4^j
II: If a=^i^j+2^k,b=2^i+3^j+^k,c=^i^k, then magnitude of a+2b3c is 78

A
Only I is true
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B
Only II is true
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C
Both I and II are true
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D
Neither l nor ll are true
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Solution

The correct option is C Both I and II are true
Consider Statement I
a+b+c
=(3i2j+k)+(2i4j3k)+(i+2j+2k)
=(3+21)i+(24+2)j+(13+2)k
=4i4j
Hence statement 1 is true.
Consider Statement 2
a+2b3c
=(ij+2k)+(4i+6j+2k)(3i3k)
=(1+43)i+(1+6)j+(2+2+3)k
=2i+5j+7k
|2i+5j+7k|
=4+25+49
=78
Hence statement 2 is true.

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