You visited us 1 times! Enjoying our articles? Unlock Full Access!

Fruendlich Isotherm

I, II and III...

Question

I, II and III are three adsorption isotherms at three temperatures $T_{1}$ , $T_{2}$ and $T_{3}$ , where $x$ is the amount of adsorbate adsorbed per $m g$ of the adsorbent.
The temperatures $T_{1}$ , $T_{2}$ and $T_{3}$ are in the order

T_{1} < T_{2} < T_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

T_{1} = T_{2} = T_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T_{3} < T_{2} < T_{1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

No specific order

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $T_{1} < T_{2} < T_{3}$
Adsorption is an exothermic process. As temperature increases, the extent of adsorption decreases.
Extent of adsorption $(\frac{x}{m})$ is minimum at $T_{3}$ and is maximum at $T_{1}$ .

Thus, $T_{1} < T_{2} < T_{3}$

Suggest Corrections

Similar questions

T_{1}

T_{2}

T_{3}

x

m g

T_{1}

T_{2}

T_{3}

I, II and III are three isotherms respectively at $T_{1}$ , $T_{2}$ and $T_{3}$ temperatures. The order of temperature will be

T_{1}, T_{2}

T_{3}

I, I I, I I I

T_{1}, T_{2}

T_{3}

T_{1}, T_{2} a n d T_{3}

Join BYJU'S Learning Program