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Question 5 (i)
Line l is the bisector of an angle A and B is any point on l. BP and BQ   are perpendiculars from B to the arms of A (see the given figure). Show that:
ΔAPBΔAQB


Solution

ΔAPB and ΔAQBAPB=AQB(Each 90)PAB=QAB(l is angle bisector of A)AB=AB(Common)ΔAPBΔAQB(By AAS Congruence Rule)

Mathematics

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