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Question

(i) Position vector A (1) 2^i+^j
(ii) Postion vector B (2) 3^i+3^j
(iii) Displacement dAB (3) 5^i+4^j
(iv) Position vector of point of
intersection of path 1 & path 2
(4) 4^i+3^j

  1. (i) - (2), (ii) - (3), (iii) - (1), (iv) - (4)

  2. (i) - (4), (ii) - (1), (iii) - (3), (iv) - (2)

  3. (i) - (3), (ii) - (1), (iii) - (2), (iv) - (4)

  4. (i) - (1), (ii) - (2), (iii) - (3), (iv) - (4)


Solution

The correct option is C

(i) - (3), (ii) - (1), (iii) - (2), (iv) - (4)


(i) From the diagram, you can see that A is at (5,4). position vector is 5^i+4^j.
(ii) Similarly, B is 2^i+^j.
(iii) dAB is the displacement vector if you move from B to A. dAB=AB
=5^i+4^j(2^i+^j)
=3^i+3^j
You can also see that if you shift the origin to B, the position vector of A becomes, 3^i+3^j.
(iv) Point of intersection is at 4^i+3^j

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