(i) The refractive index of glass with respect to air is $1.5$ . What is the value of the refractive index of air with respect to glass?
(ii) A ray of light is incident as a normal ray on the surface of separation of two different media. What is the value of the angle of incidence in this case?

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Solution

(i) Refractive index of glass with respect to air $=1Refractive index of air with respect to glass$

$_{g} μ_{a}$ = refractive index of air with respect to glass.
$_{a} μ_{g}$ = refractive index of glass with respect to air.
$_{g} μ_{a} = \frac{1}{_{a} μ_{g}} = \frac{1}{1.5} = \frac{10}{15}$

$_{g} μ_{a} = \frac{2}{3} = 0.667$

(ii) Angle of incidence $= 0^{o}$ .
Angle of incidence is defined as the angle between the incident ray and the normal to the surface of separation of the two media.

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(i) The refractive index of glass with respect to air is 1.5. What is the value of the refractive index of air with respect to glass?(ii) A ray of light is incident as a normal ray on the surface of separation of two different media. What is the value of the angle of incidence in this case?

(i) The refractive index of glass with respect to air is $1.5$ . What is the value of the refractive index of air with respect to glass?
(ii) A ray of light is incident as a normal ray on the surface of separation of two different media. What is the value of the angle of incidence in this case?